Dear Osman,
For Gregorian calendar, you could use isleapyear()
rather than calculating simply a modulo with %.
ncl 0> print(isleapyear(2004))
(0) True
ncl 1> print(isleapyear(2000))
(0) True
ncl 2> print(isleapyear(1900))
(0) False
if (isleapyear(year)) then
On 2004/05/14, at 6:07, Adam Phillips wrote:
> if (year%4.eq.0) then
> print("Leap Year")
> end if
-----
Dr. Takeshi Enomoto
eno AT jamstec.go.jp
Earth Simulator Center
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