# Re: arranging missing values in array

Date: Tue, 05 Jun 2007 10:51:23 -0600

Hi Deniz,

The following works for your simplified example. Hopefully you can use
it as a good starting point for your problem:

begin
f = (/(/1,0.15/),(/2,1.5/),(/3,0.8/),(/6,2.4/),(/9,2.0/),(/10,1.8/)/)
dimt = dimsizes(f)

if (dimt(0).ne.10) then
f2 = new((/10,2/),typeof(f),-999.)
f2(:,0) = ispan(1,10,1)
do gg = 0,dimt(0)-1
f2(floattointeger(f(gg,0))-1,:) = (/ f(gg,:) /)
end do
print(f2)
end if
end

Good luck,

deni boz wrote:
> Hi all,
>
> I want to arrange an array containing missing values ,in fact, that are
> not shown in array itself.
>
> For instance, I want to have an array consisting of test results from 1
> to 10 that also shows missing values of any test result. However, the
> form of array is like that
>
> f = (/(/1,0.15/),(/2,1.5/),(/3,0.8/),(/6,2.4/),(/9,2.0/),(/10,1.8/)/)
>
> where results of fourth, fifth, seventh, and eighth are not included in
> the array. I want to assign these values as missing values in the array.
>
> How can I do this?
>
> Any comment will be appreciated. Thanks a lot!
>
> Deniz
>
>
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