Re: Fwd: dimension size parameter error

 Hi Mary.
I understand. Thank you.
I don't think that I would have figures this out unless I asked.
When would the floor function be used, if its already implicit?
-Erik

On 2/6/08 6:10 PM, "Mary Haley" <haley_at_ucar.edu> wrote:

>
> Erik,
>
> You don't need to use a function here, if "ntimes" is already an
> integer. Just use:
>
> nvtimes = (ntimes-1)/8
>
> When you do integer arithmetic on the right side of the equation, NCL
> will return an integer. And, it will effectively do what "floor"
> does for floats/doubles.
>
> Hence, "n = 5/3" will give you 1, "n = 2/3" will give you 0, etc.
> "487/8 " will give you 60.
>
> --Mary
>
> On Wed, 6 Feb 2008, Erik Noble wrote:
>
>> Hi.
>> I realize that this is a problem with the "floor' command. Any suggestions?
>>
>>
>> ---------- Forwarded message ----------
>> From: Erik Noble <enoble_at_giss.nasa.gov>
>> Date: Feb 6, 2008 3:38 PM
>> Subject: dimension size parameter error
>> To: "ncl-talk_at_ucar.edu" <ncl-talk_at_ucar.edu>
>>
>>
>> Hi.
>> I am getting an error that says:
>> "fatal:New: the dimension size parameter is the wrong type an integer
>> value was expected"
>>
>> when i have this syntax in my code
>> nvtimes = floor((ntimes-1)/8) ntimes = 487, nvtimes should equal "60"
>> print(nvtimes)
>> V925 = new((/nvtimes, 109, 139/),"float")
>>
>> But when I just state an integer, I do not get an error.
>> nvtimes = 60
>> print(nvtimes)
>> V925 = new((/nvtimes, 109, 139/),"float")
>>
>> Variable: nvtimes
>> Type: integer
>> Total Size: 4 bytes
>> 1 values
>> Number of Dimensions: 1
>> Dimensions and sizes: [1]
>> Coordinates:
>> (0) 60
>>
>> How can I correct calling in the named dimension size parameter?
>> -Erik
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>
Received on Wed Feb 06 2008 - 20:13:16 MST