Re: the calculation of potential temperature

From: Dennis Shea <shea_at_nyahnyahspammersnyahnyah>
Date: Tue, 14 Oct 2008 17:52:04 -0600

if T (K) and P (mb) have the same dimensions (say) (time,lev,lat,lon)

    theta = T*(1000/P)^0.236
=============================

If T(time,lev,lat,lon) and P(lev)

   theta = T*(1000/conform(T,P,1))^0.286

==============================

Good luck
D

WZQ wrote:
> Hi everyone, I want to calculate potential temperature to get a plot
> with NCL.. I want to know if there is a NCL function which can be
> directly use to perform this computation??? thanks...
> I
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Received on Tue Oct 14 2008 - 17:52:04 MDT

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