Re: Vertical averaging using varying depths

Hi Dennis,
 A more fundamental constraint is the size of my data: 624x29x193x256 and 624x193x256, which exceed 2G by far even before I create additional arrays. I'll therefore have to subset at some fixed levels and average directly. Thanks for your repeated hints, they may be useful for me elsewhere.
Hyacinth

> Date: Wed, 23 Jan 2013 10:10:47 -0700
> From: shea@ucar.edu
> To: hyacinth.1@hotmail.com
> CC: ncl-talk@ucar.edu
> Subject: Re: Vertical averaging using varying depths
>
> The denominators should have a 2nd argumenty
>
> dim_sum_n(dz) ==> dim_sum_n(dz , 0)
> dim_sum_n(dz4) ==> dim_sum_n(dz4, 1) ;
>
> On 01/23/2013 09:09 AM, Hyacinth Nnamchi wrote:
> > Thanks for your response Dennis, I'll try out your suggestion.
> >
> > Hyacinth
> >
> >
> >
> > > Date: Mon, 21 Jan 2013 11:26:15 -0700
> > > From: shea@ucar.edu
> > > To: hyacinth.1@hotmail.com
> > > CC: ncl-talk@ucar.edu
> > > Subject: Re: Vertical averaging using varying depths
> > >
> > >
> > > There can not be function for everything.
> > > You can always write your own.
> > > Also, is the (x,y,z,t) fortran ordering???
> > > Is 'z' one dimensional or 4 dimensional?
> > >
> > > let: dz=layer_thickness,
> > > q=variable, fortran(x,y,z,t)=>ncl(t,z,y,x) ; 0,1,2,3
> > >
> > > z_zavg = dim_sum_n(q*dz, 1)/dim_sum_n(dz) ; q and dz (x,y,z,t)
> > > --
> > > dz4 = conform(dz,z,1)
> > > z_zavg = dim_sum_n(q*dz4, 1)/dim_sum_n(dz4) ; q(x,y,z,t), dz(z)
> > >
> > > On 1/21/13 10:00 AM, Hyacinth Nnamchi wrote:
> > > >
> > & gt; > Hi users,
> > > > I want to calculate the vertical average of a 4D (x,y,z,t) ocean
> > variable. The problem is that the depths will have to vary: I want to
> > use the thermocline depth (already calculated, x,y,t) as the base at
> > each grid point, for the vertical vertical averaging. Is there a
> > way/function to do this ncl?
> > > > Thanks in advance.
> > > > Hyacinth
> > > >
> > > >
> > > >
> > > >
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Received on Thu Jan 24 04:22:27 2013