Re: extracting components of date from csv file

From: Dennis Shea <shea_at_nyahnyahspammersnyahnyah>
Date: Wed Dec 11 2013 - 07:10:32 MST

Did you look the File I/O examples or the string functions?

ncl 1> date = "2012-07-07 00:15:00+00"
ncl 2> delim = "- :+"
ncl 3> nfld = str_fields_count(date,delim)
ncl 4> print("nfld="+nfld)
ncl 5> year = str_get_field(date, 1, delim) ; type string

For integer, use 'toint'

year = toint( str_get_field(date, 1, delim) ) ; type integer

---
http://www.ncl.ucar.edu/Document/Functions/
Under "General NCL routines" click 'String'
http://www.ncl.ucar.edu/Applications/
Under 'File I/O" click 'Read CSV Files'
On 12/10/13, 11:08 PM, sangeeta maharjan wrote:
> Hello NCL Users,
>
> Our meteorological station stores data in csv format. It stores data
> in the interval of 15 minutes . The stored dates are 2012-07-07
> 00:15:00+00, 2012-07-07 00:30:00+00, 2012-07-07 00:45:00+00,
> 2012-07-07 01:00:00+00 type.
>
> I need to extract year, month, day, hour and minutes seperately.
>
>
> I would appreciate any help on it.
>
> Thanks.
> Sangeeta Maharjan.
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Received on Wed Dec 11 07:10:43 2013

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