Thanks,
But, what should I change to get what I want (11/28)? I tried changing the
units to "2012-1-0" but that did not work and it gave me _FillValues.
-A.J.
On Fri, Dec 6, 2013 at 2:23 PM, Daniel Barandiaran
<dbarandiaran@gmail.com>wrote:
> Hi A.J.,
>
> the units on jjj are "days since 2012-1-1", so 1 is 2012-1-2, and 0 is
> 2012-1-1. That's why you are getting 11-29 for day 333.
>
>
> On Fri, Dec 6, 2013 at 3:18 PM, A.J. Eiserloh <arthur.eiserloh@gmail.com>wrote:
>
>> Hi, I know that the Julian day 333 of the year 2012 is 11/28/2012.
>> However, when I use cd_calendar() to try and give me the date of the year,
>> it gives me 11/29 instead. Why is this so and how can I fix this. This is
>> what I type in ncl. I also know that 2012 was a leap year.
>>
>> jjj=333
>> jjj@units="days since 2012-1-1"
>> jjj@calendar="julian"
>> doy=cd_calendar(jjj,-2)
>>
>> output:
>>
>> (0) 20121129
>>
>> --
>> Arthur J. Eiserloh, Jr.
>> San Jose State University
>> Graduate Student
>> Dept. of Meteorology and Climate Science
>>
>> _______________________________________________
>> ncl-talk mailing list
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>>
>>
>
>
> --
> Danny Barandiaran
> Department of Plants, Soils, and Climate
> Utah State University
>
>
>
-- Arthur J. Eiserloh, Jr. San Jose State University Graduate Student Dept. of Meteorology and Climate Science
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Received on Fri Dec 6 15:30:16 2013
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