Re: dim_minind_n / dim_maxind_n

I meant:
x_min0 = dim_min_n(x,0)
Not dim_avg_n ....



On 11/07/14 3:03 PM, Jatin Kala wrote:
> Hi all,
> i have an n-dimensional array, lets say x(a,b,c,d). I want to find the
> min along the first dimension, so i do:
> x_min0 = dim_avg_n(x,0)
>
> x_min0 is size(b,c,d)
>
> But i also want an array of same size (b,c,d) as x_min0, which has the
> indices of the min values.
>
> Most languages have a function for this, e.g., numpy.argmax(x,axis=0)
> for python, and MAXLOC/MINLOC (e.g., MAXLOC(x,dim=1)) in Fortran.
>
> There does not seem to be an NCL equivalent????
> ind_resolve does not do this, as in the case of a 4D array, it returns
> a 1 by 4 array.
>
> It's friday and i might be missing something obvious....
>
> Any comments?
> I also tried to use use WRAPIT by making a F90 subroutine which uses
> MAXLOC, but it's doing my head in!
>
> Cheers,
> Jatin.
>
>
>
>
>
>

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Received on Fri Jul 11 05:06:07 2014