>
> I have a simple question regarding the function lonFlip:
>
> When the variable (i.e. temperature) is changed from 0-360 to
>-180-180, does the original "0" corresponds to "-180" in the
>longitude?
No ... it is still 0
It is quite confusing when we just have one example to
>look at. Also, the only example comes out without orientation such as
>"-180 = 180 W", "0 = 0 E".
-180 = 180W = 180E = 180
0 = 0W = 0E
>
If the variable, (say) T, has coordinates variables, then
ncl 2> T = f->T
ncl 3> printVarSummary(T)
Variable: T
Type: float
Total Size: 17694720 bytes
4423680 values
Number of Dimensions: 4
Dimensions and sizes: [time | 30] x [lev | 18] x [lat | 64] x [lon | 128]
Coordinates:
time: [ 107.. 136]
lev: [4.8093..992.5282]
lat: [-87.8638..87.8638]
lon: [ 0..357.1875]
^^^^^^^^^^^^^^
ncl > print(T&lon)
(0) 0
(1) 2.8125
(2) 5.625
[snip]
(62) 174.375
(63) 177.1875
(64) 180
(65) 182.8125
(66) 185.625
[snip]
(125) 351.5625
(126) 354.375
(127) 357.1875
ncl 5> T = lonFlip(T)
ncl 6> printVarSummary(T)
Variable: T
Type: float
Total Size: 17694720 bytes
4423680 values
Number of Dimensions: 4
Dimensions and sizes: [time | 30] x [lev | 18] x [lat | 64] x [lon | 128]
Coordinates:
time: [ 107.. 136]
lev: [4.8093..992.5282]
lat: [-87.8638..87.8638]
lon: [-180..177.1875]
^^^^^^^^^^^^^^^^^
ncl 10> print(T&lon)
(0) -180 This is the original 180
(1) -177.1875
(2) -174.375
[snip]
(62) -5.625
(63) -2.8125
(64) 0 This is the original 0
(65) 2.8125
(66) 5.625
[snip]
(125) 171.5625
(126) 174.375
(127) 177.1875
Try the following:
t = f->T ; (time,lev,lat,lon)
tFlip = lonFlip(t)
nt = 0
kl = 10
nl = 40
print("before: "+t&lon +" "+ t(nt,kl,nl,:) +" "+ \
"after : "+tFlip&lon +" "+ tFlip(nt,kl,nl,:) )
good luck
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Received on Wed Nov 09 2005 - 15:41:55 MST
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