I do not know if WRF has a preferred equation but, I think,
all you need is temperature. Take a look at:
http://cires.colorado.edu/~voemel/vp.html
Many of these are of the form
log(pw) = ...
You will have to modify slightly to return pw
The simplest is Bolton's formula:
pw = 6.112 exp(17.67 * t / (t+243.5) ) ; t in degC ; pw will be hPa
===================
You can check answers against
http://www.s-ohe.com/Water_cal.html
Good luck
D
Gerry Creager wrote:
> Does anyone already have a canned function to calculate water vapor
> pressure from WRF output? If not, it appears trivial to write, but
> there's no sense writing it if someone else already has!
>
> gerry
>
-- ====================================================== Dennis J. Shea tel: 303-497-1361 | P.O. Box 3000 fax: 303-497-1333 | Climate Analysis Section | Climate & Global Dynamics Div. | National Center for Atmospheric Research | Boulder, CO 80307 | USA email: shea 'at' ucar.edu | ====================================================== _______________________________________________ ncl-talk mailing list List instructions, subscriber options, unsubscribe: http://mailman.ucar.edu/mailman/listinfo/ncl-talkReceived on Wed Mar 04 2009 - 13:18:41 MST
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