# Re: time coordinate in netcdf data

From: Dennis Shea <shea_at_nyahnyahspammersnyahnyah>
Date: Thu, 14 May 2009 09:34:21 -0600

time1 = f->time ; "days since 1998-10-01 00:00"

time2 = g->time ; "hours since 2000-03-01 00:00

date2 = ut_calendar(time2, 0) ; datex(:,6) [array]

year = *floattointeger* <http://www.ncl.ucar.edu/Document/Functions/Built-in/floattointeger.shtml>(utc_date(:,0)) ; Convert to integer for ut_inv_calendar
month = *floattointeger* <http://www.ncl.ucar.edu/Document/Functions/Built-in/floattointeger.shtml>(date2(:,1))
day = *floattointeger* <http://www.ncl.ucar.edu/Document/Functions/Built-in/floattointeger.shtml>(date2(:,2))
hour = *floattointeger* <http://www.ncl.ucar.edu/Document/Functions/Built-in/floattointeger.shtml>(date2(:,3))
minute = *floattointeger* <http://www.ncl.ucar.edu/Document/Functions/Built-in/floattointeger.shtml>(date2(:,4))
second = date2(:,5) ; must be float or double

; note "time1"
TIME2 = *ut_inv_calendar*(year,month,day,hour,minute,second,time1_at_units, 0)
print(time1+" "+ time2+" "+TIME2)
or,
print(sprintf("%12.2f",time1)+" " \
+sprintf("%12.2f",time2)+" " \
+sprintf("%12.2f",TIME2) )

Good Luck
D
=======================
Kai Zhang wrote:
> Dear all,
>
> I have two netcdf data files which use different time coordinates. One file is
>
> time:units = "days since 1998-10-01 00:00" and the other file is
>
> time:units = "hours since 2000-03-01 00:00".
>
> Is there a simple or well-developed method to convert the time
> coordinate in second netcdf data to the same time coordinate in the
> first data?
>
> Thanks!
>
> Best regards, Kai
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Received on Thu May 14 2009 - 09:34:21 MDT

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