Re: reading in binary data

There is a general writeup on how to figure out Fortran binary, at
the bottom of this NCL page. Try factoring the file size 2908872,
and see if it makes sense:

   http://www.ncl.ucar.edu/Applications/r-binary.shtml

--Dave

On 10/27/2011 12:13 PM, Joe Grim wrote:
> Hi Dennis,
>
> 2908872, so it is barely over 1200x1200x2=2880000.
>
> Thanks for your help.
>
> Joe
>
> On 10/27/2011 12:08 PM, Dennis Shea wrote:
>> What is the size of the file in bytes?
>>
>> %> ls -l file_name
>>
>> Is it 1200*1200*2 or 1200*1200*4 ?
>>
>> Or are there 'extra' bytes?
>>
>> ===
>> The defuult in fortran is to write 'sequentail' mode
>> which *silently* prepend and postpends extra bytes.
>>
>>
>> On 10/27/11 12:00 PM, Joe Grim wrote:
>>> Hi,
>>>
>>> I've been trying to read in some FORTRAN-formatted binary data using
>>> fbindirread, but have been unsuccessful thus far. The data is described
>>> by the following:
>>>
>>> type = continuous
>>> signed = yes
>>> projection = regular_ll
>>> dx = 0.00833333
>>> dy = 0.00833333
>>> known_x = 1.0
>>> known_y = 1.0
>>> known_lat = -89.99583
>>> known_lon = -179.99583
>>> wordsize = 2
>>> tile_x = 1200
>>> tile_y = 1200
>>> tile_z = 1
>>> tile_bdr=3
>>> units="meters MSL"
>>> description="Topography height"
>>>
>>> I understand most of this (e.g., the data is 1200x1200, each data point
>>> requires 2 bytes, the value can be positive or negative), but when I try
>>> to read in the data using fbindirread, I can't find a single way that
>>> works:
>>> e.g., HGT_M = fbindirread(geog_data_path+filename,0,-1,"short")
>>>
>>> If someone knows how this works, would you please help me out? I really
>>> appreciate it!
>>>
>>> Joe Grim
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Received on Thu Oct 27 12:18:35 2011