Thanks for the reply!
However, I guess you didn't understand my problem.  I want to draw the plot
in the region of (30E, 150W),
the west boundary locate at the 30E and the east boundary is at 150W. If I
just set the resource as below:
   res@mpMinLonF           = -150
   res@mpMaxLonF           = 30
then what I got is opposite to what I want.
The lonFlip or lonPivot function can transform the coordinates of (0E,360E)
to (-180E,180E), and what I want
to do is just the reverse.
Thanks!
Lin
2011/11/25 Dennis Shea <shea@ucar.edu>
> PLEASE ... do *not* repeat post to ncl-talk.
>           This is a 4-day national holiday.
>
> You have your settings incorrect. They are reversed
>
>    res@mpMinLonF           = -150
>    res@mpMaxLonF           = 30
>
>
> On 11/24/11 9:54 AM, xiang lin wrote:
>
>> Hi,all
>>
>>      I am fluent with the longitude coordinates of (0E, 360E),  but now
>> was a little puzzled when dealing with the coordinates of (-180E,175E) .
>>
>> Here below is parts of my scripts :
>>
>> ;  read the hadslp data
>>   data    =  asciiread("/Work/smi/Hadslp2_**
>> 185001-200412.dat",-1,"float")
>>   x       =  onedtond(data,(/72,37,12,155/)**)
>>   x!0     = "lon"
>>   x!1     = "lat"
>>   x!2     = "month"
>>   x!3     = "year"
>>   x&lon       =  fspan(-180.,175.,72)    ; see more details in the
>> hadslpr2's data read instruction
>>   x&lon@units = "degrees_east"
>>   x&lat       =  fspan(90.,-90.,37)
>>   x&lat@units = "degree_north"
>>   x&month     =  ispan(1,12,1)
>>   x&year      =  ispan(1850,2004,1)
>>   printVarSummary(x)
>>    ......
>>   res@mpMinLonF            = 30
>>   res@mpMaxLonF           = -150
>>
>>  I want to pick out the sub-region eastward extending from 30E to 150W,
>> but of course the above resource would cause errors for the reason that
>> mpMinLonF must be less than
>> mpMaxLonF.
>>
>> How could I set the region correctly for plot? Is there a way to
>> transform the coordinates such as (-180E, 175E) to the ones such as
>> (0E,360E)?  I know the lonFlip and lonPivot,
>> However, I don't find  a corresponding function to the opposite job.
>>
>> Thanks!
>>
>> best wish!
>>
>>
>> Lin
>>
>>
>>
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Received on Thu Nov 24 18:54:06 2011
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