About the 2-dimensiontal lon and lat

Hi, Mary
I meet with the problem of the 2-dimensional lon and lat.
dimensions:
    time = UNLIMITED ; // (1872 currently)
    j = 384 ;
    i = 320 ;
    bnds = 2 ;
    vertices = 4 ;
variables:
    double time(time) ;
        time:bounds = "time_bnds" ;
        time:units = "days since 0000-01-01 00:00:00" ;
        time:calendar = "noleap" ;
        time:axis = "T" ;
        time:long_name = "time" ;
        time:standard_name = "time" ;
    double time_bnds(time, bnds) ;
    int j(j) ;
        j:units = "1" ;
        j:long_name = "cell index along second dimension" ;
    int i(i) ;
        i:units = "1" ;
        i:long_name = "cell index along first dimension" ;
    float lat(j, i) ;
        lat:standard_name = "latitude" ;
        lat:long_name = "latitude coordinate" ;
        lat:units = "degrees_north" ;
        lat:bounds = "lat_vertices" ;
    float lon(j, i) ;
        lon:standard_name = "longitude" ;
        lon:long_name = "longitude coordinate" ;
        lon:units = "degrees_east" ;
        lon:bounds = "lon_vertices" ;

I have seen your reply to someone's same problem. But in my script I need
to choose one certain area. For example I use this function evecv =
eofunc(sst_CW({lat|20.:70.},{lon|110.:260.},time|:),1,False). So I want the
regular lon and lat. Do u know how to solve this. Attached is my script
about how to calculate the PDO. Thanks!

Best,
Ke Deng

_______________________________________________
ncl-talk mailing list
List instructions, subscriber options, unsubscribe:
http://mailman.ucar.edu/mailman/listinfo/ncl-talk