Re: extracting components of date from csv file

From: sangeeta maharjan <sangeetamaharjan_at_nyahnyahspammersnyahnyah>
Date: Wed Dec 11 2013 - 22:50:16 MST

Hi Dennis,

It's working.

Thank You.

Sangeeta Maharjan.

On 12/11/13, Dennis Shea <shea@ucar.edu> wrote:
> Did you look the File I/O examples or the string functions?
>
> ncl 1> date = "2012-07-07 00:15:00+00"
> ncl 2> delim = "- :+"
> ncl 3> nfld = str_fields_count(date,delim)
> ncl 4> print("nfld="+nfld)
> ncl 5> year = str_get_field(date, 1, delim) ; type string
>
> For integer, use 'toint'
>
>
> year = toint( str_get_field(date, 1, delim) ) ; type integer
>
> ---
> http://www.ncl.ucar.edu/Document/Functions/
> Under "General NCL routines" click 'String'
>
> http://www.ncl.ucar.edu/Applications/
> Under 'File I/O" click 'Read CSV Files'
>
>
>
> On 12/10/13, 11:08 PM, sangeeta maharjan wrote:
>> Hello NCL Users,
>>
>> Our meteorological station stores data in csv format. It stores data
>> in the interval of 15 minutes . The stored dates are 2012-07-07
>> 00:15:00+00, 2012-07-07 00:30:00+00, 2012-07-07 00:45:00+00,
>> 2012-07-07 01:00:00+00 type.
>>
>> I need to extract year, month, day, hour and minutes seperately.
>>
>>
>> I would appreciate any help on it.
>>
>> Thanks.
>> Sangeeta Maharjan.
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>
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Received on Wed Dec 11 22:50:30 2013

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