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greg2jul

Converts Gregorian dates to astronomical Julian days.

Prototype

	function greg2jul (
		year   : integer,  
		month  : integer,  
		day    : integer,  
		hour   : integer   
	)

	return_val [dimsizes(year)] :  integer or double

Arguments

year

Integer array of any dimensionality. Must be >= 0.

month

Integer array of any dimensionality. Must be from 1 to 12.

day

Integer array of any dimensionality. Must be from 1 to 31.

hour

Integer array of any dimensionality. Must from 0 to 23, or the values can all be negative if you don't want the hour to enter into the calculation.

Return value

An array of the same size as year. The type is integer if the values of hour are negative, and double otherwise.

Description

Converts a Gregorian date to a astronomical Julian day. A Julian day is defined as the number of days since January 1, 4713 B.C. A Julian day begins at noon Universal Time [UT; 12Z] of the given date (Fliegel & Van Flandern, (1968), A Machine Algorithm for Processing Calendar Dates, Communications of the ACM 11 No. 10, p657)

In V6.1.0. this function was upgraded to recognize missing values.

See Also

jul2greg, day_of_year, days_in_month, day_of_week, monthday, isleapyear, cd_calendar, cd_inv_calendar

Examples

Example 1

 juli = greg2jul(-4713,11,25,0) ;  ==>  juli = 0.5 (middle of Gregorian julian day reference date)
                                                         
 juli = greg2jul(0,1,1,0)       ;  ==>  juli = 1721059.5 (1st day of 1 BC)
 juli = greg2jul(1582,10,15)    ;  ==>  juli = 2299160.5 (1st day of Gregorian reform)
 juli = greg2jul(1900,1,1,-1)   ;  ==>  juli = 2415021

 juld = greg2jul(1900,1,1,0)    ;  ==>  juld = 2415020.5
 juld = greg2jul(1900,1,1,6)    ;  ==>  juld = 2415020.75 
 juld = greg2jul(1900,1,1,12)   ;  ==>  juld = 2415021. 
 juld = greg2jul(1900,1,1,18)   ;  ==>  juld = 2415021.25 

 year  = (/1950,1960,1970,1980,1990,2000,2500/)
 month = (/   1,   1,   1,   7,   1,   1,  12/)
 day   = (/   1,   1,   1,  15,   1,   1,  31/)
 hour  = (/  -1,  -1,  -1,  -1,  -1,  -1,  -1/)
 
 julim = greg2jul (year,month,day,hour) ; returns      (0)  2433283
                                        ; (1)  2436935 (2)  2440588 
                                        ; (3)  2444436 (4)  2447893 
                                        ; (5)  2451545 (6)  2634531
		
 hour  = (/  0,  3,  6,  9,  12,  15,  18/)
 juldm = greg2jul (year,month,day,hour)  ; returns         (0) 2433282.5
                                         ; (1) 2436934.625 (2) 2440587.75
                                         ; (3) 2444435.875 (4) 2447893
                                         ; (5) 2451545.125 (6) 2634531.25
     
 
Example 2

Time in the form of "days since 1900-1-1 00:00:0.0" is desired. ut_calendar and ut_inv_calendar are appropriate for handling time in these units.

     base_julian = greg2jul(1900,1,1,0)    ;  ==>  2415020.5
     
     new_julian  = greg2jul(1993,1,1,0) - base_julian
Example 3

Construct Julian day function:

undef("newJulian")
function newJulian (yr,mo,dy,hr, yrBase,moBase,dyBase,hrBase)
begin
  return(greg2jul(yr,mo,dy,hr) - greg2jul(yrBase,moBase,dyBase,hrBase))
end